Title

Challenge 2 below: Complete the Min and Max procedure in either JavaScript and Python using the instructions from the JavaScript page. (JavaScript will get you a extra 0.1)

function findMax(numA, numB) {
    if (numA > numB) {
        return(numA + " is greater than " + numB);

    }
    else {
        return(numB + " is greater than " + numA)
    }
}

function findMin(numA, numB) {
    if (numA < numB) {
        return(numA + " is less than " + numB);
        
    }
    else {
        return (numB + " is less than " + numA);
    
    }
}

console.log(findMax(54, 45));

console.log(findMin(100000, 7));

54 is greater than 45
7 is less than 100000